Nibiru parameters

Summary:

What are the Nibiru parameters?

Nibiru parameters

obaeyens 04 Nov 2010 21:03

Hello, I am new to this site and I love it.

I am interested in astronomy so that is where my debunking lays. But it is hard to debunk something if none of the Nibiru proponents understand themselves any astronomy and make up their claims.

I needs some parameters:
What is the mass of Nibru?
How close does it get to Earth?
What is it’s orbital period. 3600 every turn? And why?

I already have a first Youtube clip intended to debunk the claims, but needs parameters.
http://www.youtube.com/watch?v=AzaVprzVki8

Re: Nibiru parameters

obaeyens 04 Nov 2010 21:31

I have been busy doing some calculations.

In order to have a same attracting factor on the surface of the Earth like the Moon has,
It only means that the sea levels is twice higher, so no huge tsunami!

Stuff that none of the Nibiru experts are able to calculate.

• 5 Jupiter Mass Nibiru would be closer than 0.923597 AU
• 1 Jupiter mass 0.413045 AU
• 1 Earth Mass Nibiru 0.0231697 AU

Re: Nibiru parameters

obaeyens 04 Nov 2010 22:38

I also want to add some additional numbers.

The Moon is pulling at 1 kg mass on Earth with a force of

• Front side 0.000033191 Newton
• Back side 0.0000331866 Newton
• The force differential is 4.40538×10-9 Newton

Now when I do the calculation for a 4 Earth mass planet at the distance where it has the same pull as a the Moon, this is
at 0.0463394 I get these numbers

• Front side 0.0000331889 Newton
• Back side 0.0000331887 Newton
• The force differential is 2.44281×10-10 Newton

The force difference between the front side of Earth and the backside is 18.0341 times less than the pull of the Moon because it is much further away.
For a 5 Jupiter mass planet at the distance where it has the same pull as a the Moon, this is at 0.923597 I get these numbers

• Front side 0.0000331888 Newton
• Back side 0.0000331888 Newton
• The force differential is 1.22562×10-11 Newton

The force difference between the front side of Earth and the backside is 359.44 times less than the pull of the Moon because it is much further away.

In short, the bigger the mass of the planet is, the smaller the force gradient becomes between the front and back of Earth, the less effect it has on Earth quakes, Volcano’,… only on the water.

And I did not mention that Nibiru moves at 42 km/s and earth 30 km/s so gravitationally it does not get any effect on Earth to have any meaning. (I must still do some calculations to confirm this.)

Re: Nibiru parameters

3WMElliott 04 Nov 2010 22:11

What is the mass of Nibiru?

You'll hear anything from 4 times to mass of Earth to 4 or 5 times the mass of Jupiter usually. Nobody can agree of course, throws a bit of a spanner in the works…

How close does it get to Earth?

Again, the consensus is of 'no impact, just a fly by', but that it will go between either the Earth and the Sun, or Mars and Jupiter. But seeing as between Mars and Jupiter is nothing interesting (and by interesting proponents generally mean 'Earth'), it's usually the former.

What is it’s orbital period. 3600 every turn? And why?

Dates back to Zechariah Sitchin, though I think some others have done some numerology nonsense around it. It seems to be the number everyone agrees on, though you'll get disagreements over when it gets close, rather than how long. Again 2012, as this site suggests, is the first number to come about, and not the dates offered by Sitchin himself, who was closer to 2112 than 2012.

Funny how proponents just don't care about the details. But it's good to see yet more YouTube firepower against these claims, keep it up.

Last edited on 04 Nov 2010 22:12 by 3WMElliott Show more

Re: Nibiru parameters

obaeyens 04 Nov 2010 22:19

it will go between either the Earth and the Sun

When you look at the eccentricity, of the orbit this is even more unstable than between Mars and Jupiter. One of my simulations slings-hotted Nibiru out of this solar system.

4 times to mass of Earth

That would mean that it needs to get closer than 0.0463394 AU to have the same level as attraction force as out Moon.

So far all the planets are exactly at the places where they are so a 5 Jupiter mass is out of the question.

Re: Nibiru parameters

3WMElliott 04 Nov 2010 22:29

Therein lies much of the problem for proponents: a number like 0.0463394 AU is two orders of magnitude too weird to be imaginable. They like round numbers. Big, easy to remember, round numbers.

No, wait.

Therein lies much of the problem for proponents: Science.

Re: Nibiru parameters

obaeyens 04 Nov 2010 22:52

One 100% proven method to chase away any conspiracy theorists is when you give numbers and formula's! :-)
Even if your maths are wrong, they all run away. LOL

Re: Nibiru parameters

obaeyens 04 Nov 2010 22:58

Therein lies much of the problem for proponents: a number like 0.0463394 AU is two orders of magnitude too weird to be imaginable. They like round numbers. Big, easy to remember, round numbers.

Ah OK

To have the same force as our moon, Nibiru would be closer than:

* 5 Jupiter Mass Nibiru 359 Moon distances
* 1 Jupiter Mass Nibiru 161 Moon distances
* 4 Earth Mass Nibiru 18 Moon distances
* 1 Earth Mass Nibiru 9 Moon distances

Last edited on 04 Nov 2010 23:17 by obaeyens Show more

Re: Nibiru parameters

Rocksio 10 Dec 2010 01:56

Nothing because the object dose not exists